The perimeter of a rectangle garden is 42 ft. The length of the garden is 5 ft more than twice the width. Which system of equations will determine the length & the width of the garden?
I m not really sure how to do this so if someone could explain that would be great! Thanks so much for the help!
Help with this math problem...?
2015-12-02 6:58 am
回答 (2)
2015-12-02 7:30 am
ω: width of the garden
ℓ: length of the garden
The perimeter of a rectangle garden is 42 ft.
2.(ω + ℓ) = 42
ω + ℓ = 21 → the length is 5 ft more than twice the width: ℓ = 2ω + 5
ω + 2ω + 5 = 21
3ω = 16
→ ω = 16/3 ft
Recall: ℓ = 2ω + 5
ℓ = 2.(16/3) + 5
ℓ = (32/3) + (15/3)
ℓ = (32 + 15)/3
→ ℓ = 47/3 ft
ℓ: length of the garden
The perimeter of a rectangle garden is 42 ft.
2.(ω + ℓ) = 42
ω + ℓ = 21 → the length is 5 ft more than twice the width: ℓ = 2ω + 5
ω + 2ω + 5 = 21
3ω = 16
→ ω = 16/3 ft
Recall: ℓ = 2ω + 5
ℓ = 2.(16/3) + 5
ℓ = (32/3) + (15/3)
ℓ = (32 + 15)/3
→ ℓ = 47/3 ft
2015-12-02 7:10 am
l+w=21
l=5+2w
l=5+2w
收錄日期: 2021-04-21 15:30:03
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