Demand function help needed in Calculus :(?
Having a hard time with this. Anyone know how to calculate it?
回答 (1)
1. E = ?
q(x) = √(350-x^3)
q' = -3x^2 / 2√(350-x^3)
E = -x/q * q'
= -x/√(350-x^3) * -3x^2/2√(350-x^3)
= 3x^3 / 2(350-x^3)
2. E = ? for x = 5
E = 3*125 / 2(350 - 125)
= 3*125 / 2*225
= 3*5 / 2*9
= 5/6
3. q^2 = 350 - x^3
2qq' = -3x^2*x'
x' = -2qq'/2x^2
Thus x' will be decreased if q'= +1 unit !!
收錄日期: 2021-04-30 20:11:13
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