Demand function help needed in Calculus :(?

2015-12-01 11:17 pm
Having a hard time with this. Anyone know how to calculate it?

回答 (1)

2015-12-01 11:38 pm
1. E = ?

q(x) = √(350-x^3)

q' = -3x^2 / 2√(350-x^3)

E = -x/q * q'

= -x/√(350-x^3) * -3x^2/2√(350-x^3)

= 3x^3 / 2(350-x^3)




2. E = ? for x = 5

E = 3*125 / 2(350 - 125)

= 3*125 / 2*225

= 3*5 / 2*9

= 5/6




3. q^2 = 350 - x^3

2qq' = -3x^2*x'

x' = -2qq'/2x^2

Thus x' will be decreased if q'= +1 unit !!


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