設f(x-1/2x-1)=3x+2，求f(1)=?

設a=(x-1)/(2x-1)
x-1=2ax-a
x(1-2a)=1-a
x=(1-a)/(1-2a)
f(x)=3(1-x)/(1-2x)+2
f(x)=(3-3x+2-2)/(1-2x)
f(x)=(5-5x)/(1-2x)
f(1)=(5-5)/(-1)
f(1)=0

(x-1)/(2x-1) = 1
x-1 = 2x-1
x = 0

f(1)
= f( (x-1)/(2x-1) = 1 )
= f( x=0 )
= 3*0 + 2
= 2 ..... Ans

令t=(X-1/2X-1)代入