設f(x-1/2x-1)=3x+2，求f(1)=?
回答 (3)
2015-12-02 12:14 am
✔ 最佳答案
設a=(x-1)/(2x-1)x-1=2ax-a
x(1-2a)=1-a
x=(1-a)/(1-2a)
f(x)=3(1-x)/(1-2x)+2
f(x)=(3-3x+2-2)/(1-2x)
f(x)=(5-5x)/(1-2x)
f(1)=(5-5)/(-1)
f(1)=0
2015-12-01 12:04 pm
(x-1)/(2x-1) = 1
x-1 = 2x-1
x = 0
f(1)
= f( (x-1)/(2x-1) = 1 )
= f( x=0 )
= 3*0 + 2
= 2 ..... Ans
x-1 = 2x-1
x = 0
f(1)
= f( (x-1)/(2x-1) = 1 )
= f( x=0 )
= 3*0 + 2
= 2 ..... Ans
2015-12-01 3:05 pm
令t=(X-1/2X-1)代入
收錄日期: 2021-04-18 14:07:48
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https://hk.answers.yahoo.com/question/index?qid=20151201032059AADUaEm