If a:b:c=2:3:5 and 3a+2b+5c=740,find the values of a,b,c (hint: Let a=2k , b=3k , c=5k , find the value of k first)?
回答 (2)
2015-11-28 11:07 am
✔ 最佳答案
Hello, yes, you need to let a=2k, b=3k, c=5k.
>>3*(2k)+2*(3k)+5*(5k)=740
>>6k+6k+25k=740
>>37k=740
>>k=20
So, a=40, b=60, c=100.⊙ω⊙
2015-11-30 11:23 am
a:b:c=2:3:5
3a+2b+5c=740
3(2k)+2(3k)+5(5k)=740
37k=740
k=20
a=40 b=60 c=100
3a+2b+5c=740
3(2k)+2(3k)+5(5k)=740
37k=740
k=20
a=40 b=60 c=100
收錄日期: 2021-04-18 14:10:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151128024758AAyJxLP