3-4i分之7+2i+3+4i分之7-2i=?
回答 (2)
2015-11-28 10:53 am
(7+2i)/(3-4i)+(7-2i)/(3+4i)
=(13+34i+13-34i)/25
=26/25
=(13+34i+13-34i)/25
=26/25
2015-11-26 2:28 pm
3-4i / 7+2i
+
3+4i / 7-2i
=
13-34i / 45
+
13+34i / 45
=
26/45
because
a+bi / c+di
=
(a+bi)(c-di) / c^2 + d^2
=
(ac+bd) + i(bc-ad)
-------------------------
c^2 + d^2
+
3+4i / 7-2i
=
13-34i / 45
+
13+34i / 45
=
26/45
because
a+bi / c+di
=
(a+bi)(c-di) / c^2 + d^2
=
(ac+bd) + i(bc-ad)
-------------------------
c^2 + d^2
收錄日期: 2021-04-11 21:17:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151126052231AA8CO9X