求數學解 設A(-3,5) B(-5,-3).求線段AB? 1.(-2,-8) 2.(2.8) 3.(-8,2) 4.(8,2) A(-4,9) B(7,2) C(5,-8) 線段AB=線段CD 求D? (座標) 只是感到疑惑 因為如果是線段應該會是距離公式 怎麼會有座標?

1.AB=[(-3-5)*2+(5-(-3))*2]根號 =8根號2
2.AB=11根號2 所以又四組解16.3 -6.3 16.-19 -6.-19

what are you asking for actually
but I can tell you:
the slope between A(x1, y1) and B(x2, y2) =
difference of y / difference of x
= (y2 - y1) / (x2 - x1)
the distance = sqrt((y2 - y1) ^ 2 + (x2 - x1) ^ 2)

3-6