How do I do this problem?

A latitudinal ("horizontal") line in the west-to-east direction forms one side of
a right triangle. That line is 50 miles long. A longitudinal ("vertical") line in the
north-to-south direction and 35 miles long forms the second side of the right
triangle. The sip is currently located at the end of the longitudinal line. The
straight-line course to port that the captain wishes to take forms the third side
of the right triangle and is the hypotenuse of the right triangle.

A = latitudinal line = 50 miles
B = longitudinal line = 35 miles
H = hypotenuse; intended course straight to port
α = angle between line B and line H = to be determined

tan α = A/B = 50/35 = 1.428571429
α = arctan (1.428571) = 55.0079798 °
α = 55.01 ° ANSWER

β = angle as measured CCW from the positive x-axis = to be determined
β = 90.00° + α = 90.00° + 55.01° = 145.00798 °
β = 145.01 ° ANSWER

ε = complementary angle to α = to be determined
ε = 90.00° - α = 90.00° - 55.01° = 34.9920202 °
ε = 34.99 °

θ = angle as measured CW from NORTH = 0° (compass bearing) = to be determined
θ = 270.00° + ε = 270.00° + 34.99° = 304.99202 °
θ = 304.99 ° ANSWER

True Bearing or Compass Bearing ?