微積分 y=x/x-1 求dy 求過程跟答案?
回答 (2)
2015-11-23 12:36 pm
✔ 最佳答案
Suppose y = x / (x - 1) = 1 + [1/(x - 1)]dy = -1/(x - 1)² dx = - dx / (x - 1)²
2015-12-04 2:58 pm
y=x/(x-1)
dy/dx=[(x-1)-x]/(x-1)^2
dy/dx=-(x-1)^-2
dy/dx=[(x-1)-x]/(x-1)^2
dy/dx=-(x-1)^-2
收錄日期: 2021-04-18 14:05:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151123041849AAesTEK