槓桿受力計算 槓桿原理?
若一臂長為6m桿重量為240kg,在4m處懸吊一點,此時臂桿向4m那側傾斜,請問2m那側需施若干kg的力,才可使此臂桿平行呢
回答 (1)
臂長: L = 6 m
懸吊: a = 4 m
桿重: w = 240 kg
重心: b = L/2 = 3 m
F*2 = 240*(a - b) = 240*1
F = 240/2 = 120 kg
收錄日期: 2021-04-30 19:56:09
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