請問大大~~下題如何解呢 一正弦波的振動頻率 3 赫茲，振幅 0.1 公尺，相鄰兩波峰相距 0.5 公尺，則在 2 秒內，弦波上某質點所經過的路徑長為多少公尺？
回答 (1)
2015-11-20 9:16 am
y(t) = 0.1*sin(2π3t) = 0.1*sin(6πt)
L(t) = 0.2*6πt/2π = 0.6*t
L(2) = 0.6*2 = 1.2 meters = Answer
L(t) = 0.2*6πt/2π = 0.6*t
L(2) = 0.6*2 = 1.2 meters = Answer
收錄日期: 2021-04-30 19:53:42
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