一顆2HP電馬達普利2in半搭配皮帶經3in普利的10:1的渦輪減速機輸出的最大公斤是多少 ?
回答 (1)
2015-11-20 9:52 am
Power = 2HP = 2*746 = 1492 watts
Pulleys = 2.5" * 3"
D2 = 3" = 3*0.0254 = 0.0762 m
Worm & Gear = 10:1
F = ? kg
N1 = 120*frequency/poles = 120*60/6 = 1200 rpm
N2 = 1200* 2.5/3 * 1/10 = 100 rpm
V = 2πD2*N2/60 = π*0.0762*100/30 = 0.798 m/s
F = Power/V*g = 1492/0.798*9.8 = 190.783 kg = Answer
Pulleys = 2.5" * 3"
D2 = 3" = 3*0.0254 = 0.0762 m
Worm & Gear = 10:1
F = ? kg
N1 = 120*frequency/poles = 120*60/6 = 1200 rpm
N2 = 1200* 2.5/3 * 1/10 = 100 rpm
V = 2πD2*N2/60 = π*0.0762*100/30 = 0.798 m/s
F = Power/V*g = 1492/0.798*9.8 = 190.783 kg = Answer
收錄日期: 2021-04-30 20:16:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151118223259AA3Caq3