【數學】雙曲線的問題?
回答 (1)
2015-11-18 8:28 pm
[(x + 1) / 4]^2 + [(y - 1) / 3]^2 = 1
a = 4, b = 3, c = √(3^2+4^2) = 5
(1) 中心 = (-1,1)
(2) 焦點 = (-1,1) + - (5,0) = (4,1) & (-6,1)
(3) 頂點 = (-1,1) + - (4,0) = (3,1) & (-5,1)
(4) 貫軸方程式: y = 1
(5) 共軛軸方程式: x = -1
(6) 正焦弦長 = 2*9/4 = 9/2
(7) 漸近線方程: (y - 1) / 3 = + - (x + 1) / 4
(A) 3x - 4y + 7 = 0
(B) 3x + 4y - 1 = 0
a = 4, b = 3, c = √(3^2+4^2) = 5
(1) 中心 = (-1,1)
(2) 焦點 = (-1,1) + - (5,0) = (4,1) & (-6,1)
(3) 頂點 = (-1,1) + - (4,0) = (3,1) & (-5,1)
(4) 貫軸方程式: y = 1
(5) 共軛軸方程式: x = -1
(6) 正焦弦長 = 2*9/4 = 9/2
(7) 漸近線方程: (y - 1) / 3 = + - (x + 1) / 4
(A) 3x - 4y + 7 = 0
(B) 3x + 4y - 1 = 0
收錄日期: 2021-04-30 20:01:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151117192956AA2bG2Z