因式分解 (ax的2次-6)+(3x-2ax) 過程麼算?
回答 (2)
2015-11-17 2:51 pm
(ax² - 6) + (3x - 2ax)
= ax² - 2ax + 3x - 6
= ax(x - 2) + 3(x - 2)
= (ax + 3)(x - 2)
= ax² - 2ax + 3x - 6
= ax(x - 2) + 3(x - 2)
= (ax + 3)(x - 2)
2015-12-26 8:57 am
(ax^2 -6)+(3x-2ax)
= ax² - 2ax + 3x - 6
= ax(x - 2) + 3(x - 2)
= (ax + 3)(x - 2)
= ax² - 2ax + 3x - 6
= ax(x - 2) + 3(x - 2)
= (ax + 3)(x - 2)
收錄日期: 2021-04-18 14:02:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151117035041AA32iO8