x平方-3x+1>等於0之解為?
回答 (2)
2015-11-16 2:33 pm
x^2-3x+1≧ 0 用公式解[-b±√ (b^2-4ac)]/2a
=[x-(3+√5)/2][x-(3-√5)/2]≧ 0
當x=0的時候x^2-3x+1為正數 (附圖)
故x≧(3+√5)/2 or x≦(3-√5)/2
=[x-(3+√5)/2][x-(3-√5)/2]≧ 0
當x=0的時候x^2-3x+1為正數 (附圖)
故x≧(3+√5)/2 or x≦(3-√5)/2
2015-12-26 8:55 am
x^2-3x+1>等於0
x=<0.3819660112501051 or x>=2.618033988749895
x=<0.3819660112501051 or x>=2.618033988749895
收錄日期: 2021-04-18 14:13:26
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