更新1:
感謝回覆！這題是我的疏失，未附上圖片，請再前往下面網頁（已附上圖片）幫我解答，感謝！ https://tw.answers.yahoo.com/question/index?qid=20151116170545AA0WBz6
請問一題國中物理: 將一小鋼球放在半圓形碗壁,使小鋼球自A點沿箭號方向自由下滑,若不計摩擦力,請問小鋼球在___ 點之處的動能與位能相等?
回答 (1)
2015-11-16 9:01 pm
✔ 最佳答案
y = Top to any point, R = Radius, R - y = Bottom to any pointPotential = m*g*(R - y)
Kinetic = 0.5*m*v^2 = m*g*y = m*g*(R - y)
==> y = R/2 = 小鋼球在_中__ 點
收錄日期: 2021-04-30 20:16:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151115184615AASrr9J