prove that a necessary and sufficient condition for a non negative integer n to be divisible by a positive integer d is that n mod d = 0?
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d|n ⇔ n ≡ 0 mod d
d|n ⇔ n=kd+0
for some positive integer k
⇔ n-0 is a multiple of d
⇔ n ≡ 0 mod d
收錄日期: 2021-04-21 15:02:25
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