方程式√3(x-2)=√2(x-3)之解為x=______?
回答 (2)
2015-11-15 3:53 pm
✔ 最佳答案
√3(x - 2) = √2(x - 3)√3 x - 2√3 = √2 x - 3√2
(√3 - √2)x = 2√3 - 3√2
x = (2√3 - 3√2) / (√3 - √2) = (2√3 - 3√2)(√3 + √2) = 6 - 3√6 + 2√6 - 6 = - √6
2015-12-24 4:31 am
√3(x-2)=√2(x-3)
3(x^2 -4x+4)=2(x^2 -6x+9)
3x^2 -12x+12=2x^2 -12x+18
x^2=6
x=√6 or x=-√6
3(x^2 -4x+4)=2(x^2 -6x+9)
3x^2 -12x+12=2x^2 -12x+18
x^2=6
x=√6 or x=-√6
收錄日期: 2021-04-18 14:06:45
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