0.1M18ml醋酸和0.1M12ml醋酸鈉形成緩衝溶液請問PH值多少?
回答 (1)
2015-11-09 9:08 pm
✔ 最佳答案
已知：CH3COOH 的 Ka = 1.8 × 10^-5 (M)
在混合溶液中：
[CH3COOH] = 0.1 × [18/(18 + 12)] = 0.06 M
[CH3COO^-] = 0.1 × [12/(18 + 12)] = 0.04 M
pH
= pKa - log([CH3COOH]/[CH3COO^-])
= -log(1.8 × 10^-5) - log(0.06/0.04)
= 4.6
收錄日期: 2021-04-18 14:01:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151109004527AArbyxT