27x^3-64 factor completely & show steps?
回答 (2)
2015-11-06 2:45 am
Difference of 2 cubes
[(3x)^3-4^3]
=(3x-4)(9x^2+12x+16)
[(3x)^3-4^3]
=(3x-4)(9x^2+12x+16)
2015-11-06 2:45 am
The first term is a cube. 27x^3 = (3x)^3
The second term is a cube. 64 = 4^3
You have a difference of cubes. Use the difference of cubes formula.
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
The second term is a cube. 64 = 4^3
You have a difference of cubes. Use the difference of cubes formula.
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
收錄日期: 2021-04-21 14:55:59
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