因式分解(x²-9)(x-1)+(x-3)(x²+3x+6)?
回答 (2)
2015-11-05 1:18 pm
✔ 最佳答案
(x-3)(x+3)(x-1)+(x-3)(x²+3x+6) = (x-3)(x²+2x-3)+(x-3)(x²+3x+6)
= (x-3)(2x²+5x+3)
= (x-3)(2x+3)(x+1)
這是作業嗎@@，錯了不負責喔~
參考: 我算的
2015-11-05 12:42 pm
Sol
(x^2－9)(x－1)+(x－3)(x^2+3x+6)
=(x－3)[(x+3)(x－1)+(x^2+3x+6)]
=(x－3)(x^2+2x－3+x^2+3x+6)
=(x－3)(2x^2+5x+3)
=(x－3)(2x+1)(x+1)
(x^2－9)(x－1)+(x－3)(x^2+3x+6)
=(x－3)[(x+3)(x－1)+(x^2+3x+6)]
=(x－3)(x^2+2x－3+x^2+3x+6)
=(x－3)(2x^2+5x+3)
=(x－3)(2x+1)(x+1)
收錄日期: 2021-04-30 20:15:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151105043753AAev5aC