Use implicit differentiation to find the derivative dy/dx when xsin(y)+ycos(x)=1. Show all your steps?

2015-11-01 7:34 am

回答 (1)

2015-11-01 7:51 am

✔ 最佳答案

sin(y) + x(dy/dx)cos(y) + (dy/dx)cos(x) + y[-sin(x)]=0
(dy/dx)[xcos(y) + cos(x)] = ysin(x) - sin(y)
dy/dx = [ysin(x) - sin(y)] / [xcos(y) + cos(x)]

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