Find d/dx[tan^2(√x)].?

2015-10-31 1:00 am

回答 (1)

2015-10-31 1:09 am
✔ 最佳答案
Sol
dTan^2 (√x)/dx
=[dTan^2 (√x)]/dTan(√x)]*[dTan(√x)/d√x]*[dx^(1/2)/dx]
=2Tan(√x)*Sec^2 (√x)]*(1/2)x^(-1/2)
=Sin(√x)/Cos(√x)*(1/Cos^2 (√x)]*x^(-1/2)
=Sin(√x)/[x^(1/2)*Cos^3 (√x)]


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