Find d/dx[tan^2(√x)].?

Sol
dTan^2 (√x)/dx
=[dTan^2 (√x)]/dTan(√x)]*[dTan(√x)/d√x]*[dx^(1/2)/dx]
=2Tan(√x)*Sec^2 (√x)]*(1/2)x^(－1/2)
=Sin(√x)/Cos(√x)*(1/Cos^2 (√x)]*x^(－1/2)
=Sin(√x)/[x^(1/2)*Cos^3 (√x)]