更新1:
a) Show that the point( 0,1) is on the curve y=[e^(-x/2)]*cos(x) b) Find the equation of the tangent line to the curve y=[e^(-x/2)]*cos(x) at the point (0,1).
a) Show that the point( 0,1) is on the curve y=[e^(-x/2)]*cos(x) b) Find the equation of the tangent line to the curve at the point (0,1).?
回答 (1)
2015-10-31 5:49 am
✔ 最佳答案
Sol(1)
e^0*Cos0=1
(2)
y=e^(－-x/2)Cosx
y’=－e^(x/2)Sinx－(1/2)e^(－x/2)Cosx
y’(0)=－(1/2)e^0*Cos0=1/2
y-1=(1/2)(x－0)
2y－2=x
x－2y+2=0
收錄日期: 2021-04-29 12:04:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151030165905AA0enxt