The same statistic problem but different ques a. What is the probability that Company B would charge more than Company A to drill a well?

Cost of A = 3500RM
Cost of B = 1000RM + 12x , where x feet are drilled
12x+1000=3500
12x= 2500
x = 2500/12 = 208.33

If more than 208.33 feet are drilled, B charges more than A
Find P( x > 208.33)

μ = 250
σ = 40
standardize x to z = (x - μ) / σ
P(x > 208.33) = P( z > (208.33-250) / 40)
= P(z > -1.0417) = 0.8508
(From normal probability table)

thankss =)