4FeCr2O4 + 8Na2Co3 + 7O2 ---> .....product
There are 100g of each reactant available. What is the limiting reactant?
Please list out working cuz im reli confused
Thanks!
limiting reagent question! help please!!!?
2015-10-25 2:34 pm
回答 (1)
2015-10-26 12:51 am
Supposing the reaction to be:
4 FeCr2O4 + 8 Na2CO3 + 7 O2 → 8 Na2CrO4 + 2 Fe2O3 + 8 CO2
(100 g FeCr2O4) / (223.8348 g FeCr2O4/mol) x (8 mol CO2 / 4 mol FeCr2O4) = 0.894 mol CO2
(100 g Na2CO3) / (105.9884 g Na2CO3/mol) x (8 mol CO2 / 8 mol Na2CO3) = 0.943 mol CO2
(100 g O2) / (31.99886 g O2/mol) x (8 mol CO2 / 7 mol O2) = 3.57 mol CO2
The FeCr2O4 produces the least amount of product, so FeCr2O4 is the limiting reactant.
[Note that the only reason to choose CO2 for the calculations was because its formula was short to type. Any of the three products would have given the same result concerning the limiting reactant.]
4 FeCr2O4 + 8 Na2CO3 + 7 O2 → 8 Na2CrO4 + 2 Fe2O3 + 8 CO2
(100 g FeCr2O4) / (223.8348 g FeCr2O4/mol) x (8 mol CO2 / 4 mol FeCr2O4) = 0.894 mol CO2
(100 g Na2CO3) / (105.9884 g Na2CO3/mol) x (8 mol CO2 / 8 mol Na2CO3) = 0.943 mol CO2
(100 g O2) / (31.99886 g O2/mol) x (8 mol CO2 / 7 mol O2) = 3.57 mol CO2
The FeCr2O4 produces the least amount of product, so FeCr2O4 is the limiting reactant.
[Note that the only reason to choose CO2 for the calculations was because its formula was short to type. Any of the three products would have given the same result concerning the limiting reactant.]
收錄日期: 2021-05-03 01:48:46
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