因式分解
84x²-91x+21=
12x²+11x-15=
2x³+16x²+30x=
7x²y²-19xy-6=
8x³y-16x²y²-42xy³=
2(x-y)²+5(y-x)-12=
(x²+2x)²-4(x²+2x)-32=?
更新1:
用=區分開一個題目,謝謝,請幫我解答一下!
回答 (3)
✔ 最佳答案
1)
84x²-91x+21
=7(4x-3)(3x-1)
2)
12x²+11x-15
=(4x-3)(3x+5)
3)
2x³+16x²+30x
=2x(x²+8x+15)
=2x(x+3)(x+5)
4)
7x²y²-19xy-6
=(xy-3)(7xy+2)
5)
8x³y-16x²y²-42xy³
=2xy(4x²-8xy-21y²)
=2xy(2x-7y)(2x+3y)
6)
2(x-y)²+5(y-x)-12
=2(x-y)²-5(x-y)-12
=[(x-y)-4][2(x-y)+3]
=(x-y-4)(2x-2y+3)
7)
(x²+2x)²-4(x²+2x)-32
=[(x²+2x)-8][(x²+2x)+4]
=(x-2)(x+4)(x²+2x+4)
因式分解
1 84x^2-91x+21
=7(12x^2-13x+3)
=7(4x-3)(3x-1)
2 12x^2+11x-15
=(4x-3)(3x+5)
3 2x^3+16x^2+30x
=2x(x^2+8x+15)
=2x(x+3)(x+5)
4 7x^y^2-19xy-6
=(7xy+2)(xy-3)
5 8x^3y-16x^2y^2-42xy^3
=2xy(4x^2-8xy+21y^2)
=2xy(2x+3y)(2x-7y)
6 2(x-y)^2+5(y-x)-12
=2(x-y)^2-5(x-y)-12
=[2(x-y)+3]*[(x-y)-4]
=(2x-2y+3)(x-y-4)
7 (x^2+2x)^2-4(x^2+2x)-32
=(x^2+2x-8)(x^2+2x+4)
=(x-2)(x+4)(x^2+2x+4)
因式分解
1 84x^2-91x+21
=7(12x^2-13x+3)
=7(4x-3)(3x-1)
2 12x^2+11x-15
=(4x-3)(3x+5)
3 2x^3+16x^2+30x
=2x(x^2+8x+15)
=2x(x+3)(x+5)
4 7x^y^2-19xy-6
=(7xy+2)(xy-3)
5 8x^3y-16x^2y^2-42xy^3
=2xy(4x^2-8xy+21y^2)
=2xy(2x+3y)(2x-7y)
6 2(x-y)^2+5(y-x)-12
=2(x-y)^2-5(x-y)-12
=[2(x-y)+3]*[(x-y)-4]
=(2x-2y+3)(x-y-4)
7 (x^2+2x)^2-4(x^2+2x)-32
=(x^2+2x-8)(x^2+2x+4)
=(x-2)(x+4)(x^2+2x+4)
收錄日期: 2021-04-18 13:57:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151024003912AA49Zgw
檢視 Wayback Machine 備份