A straight line L intersects the circle x^2+y^2-8x-4y-14=0 at two points P and Q,where P lies in quadrant 1 and Q lies in quadrant 3. M(0,3) is the mid-point of PQ.
a) find the equation of L.
b) find the coordinates of P and Q
己求a，但唔知点求b?
2015-10-24 7:34 am
回答 (1)
2015-10-24 8:51 am
✔ 最佳答案
Let C be the centre of the circle Since a straight line L intersects the circle x² + y² - 8x - 4y - 14 = 0 at two points P and Q
Find the intersection point of the straight line L and the circle
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收錄日期: 2021-04-18 13:56:24
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