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Find the value of constants a, b, and c such that the parabola y=ax^2+bx+c has tangent slope equal to -2 at x=0, tangent slope equal to 8 at x=1, and goes through the point (2,19).
Find the value of constants a, b, and c such that the parabola y=ax^2+bx+c has tangent slope equal to -2 at x=0, tangent slope equal to 8 at?
回答 (1)
2015-10-22 11:22 pm
Sol
y=ax^2+bx+c
y’=2ax+b
y’(0)=b=－2
y=ax^2-2x+c
y’(1)=2a－2=8
a=5
y=5x^2－2x+c
y(2)=20－4+c=19
c=3
y=5x^2－2x+3
y=ax^2+bx+c
y’=2ax+b
y’(0)=b=－2
y=ax^2-2x+c
y’(1)=2a－2=8
a=5
y=5x^2－2x+c
y(2)=20－4+c=19
c=3
y=5x^2－2x+3
收錄日期: 2021-04-30 19:13:55
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