(1)/(x+1)+(2)/(x+1)=-1
(x-1)+2(x+1)=-1
3x+1=-1
x=-2/3
What mistake did I make and how do I fix it?
2015-10-21 7:19 pm
回答 (4)
2015-10-21 7:28 pm
3/(x+1) = -1
3 = -x-1
x = -4
3 = -x-1
x = -4
2015-10-26 12:40 am
1/(x+1)+2/(x+1)= 3/(x+1)
2015-10-21 7:28 pm
You replaced 1/(x+1)+(2)/(x+1) with (x-1)+2(x+1) without changing the other side of the equation, and where did that (x-1) even come from?
2015-10-21 7:24 pm
You have two fractions with the same denominator of x+1. So you should multiply both sides by x+1:
1/(x+1) + 2/(x+1) = -1
1 + 2 = -1(x + 1)
3 = -x - 1
Add 1 to both sides:
4 = -x
Divide both sides by -1:
x = -4
1/(x+1) + 2/(x+1) = -1
1 + 2 = -1(x + 1)
3 = -x - 1
Add 1 to both sides:
4 = -x
Divide both sides by -1:
x = -4
收錄日期: 2021-05-02 11:19:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151021111955AAt65mS