設 f(x)=(x+1)^1/2(x+2)1/3(x+3)^1/4 求f'(x) 一微分... 這題我一直反覆算 怎麼算都是.... 1/12[(x+1)^1/-2(x+2)^2/-3(x+3)^3/-4][13x^2+55x+54 但解答...不是55x是52x...求解?
回答 (1)
2015-10-21 5:38 pm
✔ 最佳答案
現時無法上傳圖片 ... 答案的確是 ... (13x² + 55x + 54)
請看：
http://s9.postimg.org/s1io353q5/image.png
或看：
https://www.symbolab.com/solver/derivative-calculator/%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft(%5Cleft(x%2B1%5Cright)%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Cleft(x%2B2%5Cright)%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Cleft(x%2B3%5Cright)%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5Cright)/?origin=enterkey
收錄日期: 2021-04-18 13:56:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151021091254AAolXWs