請問一下第35頁的第23小題c選項怎麼求出答案~~連結在下面詳細資料，拜託幫我求出需計算過程!謝謝?

令 x 為年份, y 為撐竿跳高度紀錄值
並令其直線迴歸方程式為 y-hat = a + b*x

xbar = (1986+1900+.....+2004)/25 = 1952
ybay = (3.30+3.30+3.50+.....+5.95)/25 = 4.7848
Σ xy = 1986*3.30 + 1900*3.30 + ..... + 2004*5.95 = 234235.04
Σ x^2 = 1986^2 + 1900^2 + ..... + 2004^2 = 95285440

Sxy = Σxy - n*xbar*ybar = 234235.04 - 25*1952*4.7848 = 736.8
Sxx = Σx^2 - n*xbar^2 = 95285440 - 25*1952^2 = 27840

b = Sxy / Sxx = 736.8 / 27840 ≒ 0.0265
a = ybar - b*xbar = 4.7848 - 0.0265*1952 = - 46.9432
故直線迴歸方程式為 y-hat = - 46.9432 + 0.0265*x

y-hat(2008) = - 46.9432 + 0.0265*2008 = 6.2688 ≒ 6.27
error = ∣ 6.27 - 5.96 ∣ = 0.31

Ans:
Height = 6.27 m
Error = 0.31 m