problem in limit?

2015-10-18 6:04 am
find the lim ln(2cos2x) when x approachs to pi/6

回答 (1)

2015-10-22 10:37 am
x → π/6, ln (2cos2x) → 0

Put x = π/6 into ln (2cos2x)

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收錄日期: 2021-05-02 21:23:09
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