= lambdae^(-lambdax){1-sum_(k=1)^(h-1)[((lambdax)^(k-1))/((k-1)!)-((lambdax)^k)/(k!)]}
(10)
= lambdae^(-lambdax){1-[1-((lambdax)^(h-1))/((h-1)!)]}
睇吾明!!!!!!!!!!
吾明個STEP!!!!!!!!!?
2015-10-17 4:49 pm
回答 (1)
收錄日期: 2021-04-18 13:55:18
原文連結 [永久失效]:
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