Factorize m^2-n^2+6m-2n+8
學了a^2-b^2=(a+b)(a-b)
(a+b)^2=a^2+2ab+b^2
(a-b)^2=a^2-2ab+b^2
呢三個identity
Thx so much
F2 Maths Factorization using identites 唔該!!!?
2015-10-17 6:15 am
回答 (1)
2015-10-17 6:41 am
✔ 最佳答案
m^2-n^2+6m-2n+8 =m^2+6m+9-(n^2+2n+1)
=(m+3)^2-(n+1)^2
=(m+3+n+1)(m+3-n-1)
=(m+n+4)(m-n+2)
收錄日期: 2021-04-18 00:25:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151016221542AAPUxqM