更新1:
( x-1 ) / ( x+1) - (1/x-1) / ( 1/x+1 )
( x-1 ) / ( x+1) - (1/x-1) / ( 1/x )+1?
回答 (2)
2015-10-16 5:58 am
(x-1) / (x+1) - (1/x-1) / (1/x+1)
= (x-1) / (x+1) - (1-x) / (1+x)
= (x-1) / (x+1) + (x-1) / (x+1)
= 2(x-1) / (x+1)
= (x-1) / (x+1) - (1-x) / (1+x)
= (x-1) / (x+1) + (x-1) / (x+1)
= 2(x-1) / (x+1)
2015-10-15 12:33 pm
(x-1)/(x+1)-(1/x-1)/(1/x)+1
=(x-1)/(x+1)+(x-1)+1
=(x-1)/(x+1)+x
=(x-1+x^2+x)/(x+1)
=(x^2+2x-1)/(x+1)
=(x-1)/(x+1)+(x-1)+1
=(x-1)/(x+1)+x
=(x-1+x^2+x)/(x+1)
=(x^2+2x-1)/(x+1)
收錄日期: 2021-04-18 00:25:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151015032812AAcfNVa