Simplify sec x sin^2 x/1+sec x?
回答 (3)
2015-10-12 7:00 pm
(1/cos x) sin²x
--------------------
1 + 1/cosx
sin²x
---------------
cosx + 1
--------------------
1 + 1/cosx
sin²x
---------------
cosx + 1
2015-10-12 6:36 pm
Ans: 1-cos x
2015-10-12 6:23 pm
If sec𝚾 is part of the denominator, you need to use parentheses: sec𝚾sin²𝚾/(1+sec𝚾)
sec𝚾sin²𝚾/(1+sec𝚾) = (1/cos𝚾)(1-cos²𝚾)/(1+1/cos𝚾)
= (1-cos²𝚾) / (cos𝚾+1)
= (1+cos𝚾)(1-cos𝚾) / (cos𝚾+1)
= 1 - cos𝚾
sec𝚾sin²𝚾/(1+sec𝚾) = (1/cos𝚾)(1-cos²𝚾)/(1+1/cos𝚾)
= (1-cos²𝚾) / (cos𝚾+1)
= (1+cos𝚾)(1-cos𝚾) / (cos𝚾+1)
= 1 - cos𝚾
收錄日期: 2021-05-04 02:47:49
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