中一數學題題: solving equations(要做過裎) 1: (t-2/2)-(t+2/8)=t/4 2: 6[2(2-y)-3y]=24 3:y/2-2(y-4)/3=12-5y/6?

1: t/4 = (t-2)/2 - (t+2)/8

= [4(t-2) - (t+2)]/8

= (4t - 8 - t - 2)/8

= (3t - 10)/8

2t = 3t - 10

t = 10



2: 6[2(2-y)-3y]=24

4 = 2(2-y) - 3y

= 4 - 2y - 3y

= 4 - 5y

5y = 0

y = 0




3: (12-5y)/6 = y/2 - 2(y-4)/3

12 - 5y = 3y - 4(y-4) = -y + 16

-4y = 4

y = -1