中一數學題題: solving equations(要做過裎) 1: (t-2/2)-(t+2/8)=t/4 2: 6[2(2-y)-3y]=24 3:y/2-2(y-4)/3=12-5y/6?
回答 (1)
2015-10-13 9:41 am
✔ 最佳答案
1: t/4 = (t-2)/2 - (t+2)/8 = [4(t-2) - (t+2)]/8
= (4t - 8 - t - 2)/8
= (3t - 10)/8
2t = 3t - 10
t = 10
2: 6[2(2-y)-3y]=24
4 = 2(2-y) - 3y
= 4 - 2y - 3y
= 4 - 5y
5y = 0
y = 0
3: (12-5y)/6 = y/2 - 2(y-4)/3
12 - 5y = 3y - 4(y-4) = -y + 16
-4y = 4
y = -1
收錄日期: 2021-04-30 20:08:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151012045851AAf1feN