Albert and Paul are on the school baseball team. Albert has a batting average of .4, and Paul has a batting average of .3. That means that Albert gets a hit 40 percent of his at bats and Paul gets a hit 30 percent of his times at bat. What is the probability that both Albert and Paul are able to get hits their first time at bat?
I'm thinking you add them and it would be 70 percent but not certain
Probability?
2015-10-10 9:35 pm
回答 (2)
2015-10-10 9:44 pm
✔ 最佳答案
Remember the rules of probability:P(A and B) = P(A) x P(B) (as long as
A and B are independent).
So the answer is (.4)(.3) = 0.12
2015-10-10 11:25 pm
"I'm thinking you add them and it would be 70 percent but not certain"
well, how about 3 players
one at .4
one at .3
and one at .5 (super-hitter)
adding gives .4 + .3 + .5 = 1.2
except probability of an event is between 0 and 1 inclusive
it should be more difficult for all 3 to get a 1st hit
i would think to multiply them
<<<<<>>>>>
make the question about a fair coin flip for 3 Heads in a row at 50%
50%+50%+50 = 150% <<< this looks to be a certain event to happen
50%*50%*50 = 12.5% <<< this feels better
well, how about 3 players
one at .4
one at .3
and one at .5 (super-hitter)
adding gives .4 + .3 + .5 = 1.2
except probability of an event is between 0 and 1 inclusive
it should be more difficult for all 3 to get a 1st hit
i would think to multiply them
<<<<<>>>>>
make the question about a fair coin flip for 3 Heads in a row at 50%
50%+50%+50 = 150% <<< this looks to be a certain event to happen
50%*50%*50 = 12.5% <<< this feels better
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