Show that log base b (p/q) + log base b (q/p) = 0?
回答 (3)
2015-10-08 7:00 am
log base b (p/q) + log base b (q/p)
... log of a division becomes subtraction
= [log base b (p) - log base b (q)] + [log base b (q) - log base b (p)]
... associative prop.
= [log base b (p) - log base b (p)] + [log base b (q) - log base b (q)]
= 0 + 0 = 0
... log of a division becomes subtraction
= [log base b (p) - log base b (q)] + [log base b (q) - log base b (p)]
... associative prop.
= [log base b (p) - log base b (p)] + [log base b (q) - log base b (q)]
= 0 + 0 = 0
2015-10-08 6:54 am
b)
So (Log to base b of P) - (log to base b of Q) + (log to base b of Q) - (log to base b of P) does = 0.
So (Log to base b of P) - (log to base b of Q) + (log to base b of Q) - (log to base b of P) does = 0.
2015-10-08 6:46 am
Don't know
收錄日期: 2021-04-21 14:32:50
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https://hk.answers.yahoo.com/question/index?qid=20151007224523AAYldvg