Solve the equation e^x-4+4e^-x=0?
回答 (2)
2015-10-07 1:21 pm
e^x(e^x-4+4e^-x)=e^(2x) -4e^x+4=0
e^x=4/2 +/- √[16 -4(4)] /2=2
x=ln2
e^x=4/2 +/- √[16 -4(4)] /2=2
x=ln2
2015-10-07 1:12 pm
x = log𝚎 2
收錄日期: 2021-05-04 03:03:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151007050800AA8YeOr