Set h(x)=1+f(x)/g(x), where f and g are functions that satisfy
f(2)=2, f′(2)=3, g(2)=4 and g′(2)=1.
I am looking for h'(2)
My answer was 13/4, but it is wrong. I don't understand how to do this problem.
Derivative question?
2015-10-05 2:37 am
回答 (1)
2015-10-05 3:16 am
h = 1 + (f/g), h' = (1/g)^2[gf' - fg']. gf'(2) = 3g(2), fg'(2) = f(2) and h'(2) =
[1/g(2)]^2[3g(2) - f(2)] = [1/4]^2[3*4 - 2] = (5/8).
[1/g(2)]^2[3g(2) - f(2)] = [1/4]^2[3*4 - 2] = (5/8).
收錄日期: 2021-04-21 14:30:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151004183722AAfyvJF