It's in 2 parts. The first tells me to differentiate ln(x^2+1)/x. The answer is:
..... 2 ....... − .. ln(x^2+1)
———— ... —————
(x^2 +1) ............ x^2
Then the next part is:
Given than x = tan y, show that dy/dx = 1/(1+x^2).
I don't know how?
I don't understand how to solve this differentiation question?
2015-10-04 6:38 pm
回答 (1)
2015-10-05 9:30 am
✔ 最佳答案
tan y = x = x / 1cos y = 1 / √( 1 + x^2 )
cos^2 y = 1 / ( 1 + x^2 )
x = tan y
dx / dx = d tan y / dx
1 = sec^2 y * dy/dx
dy/dx = 1 / sec^2 y = cos^2 y = 1 / ( 1 + x^2 )
Q.E.D.
收錄日期: 2021-05-02 14:09:24
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