[數學] Q1: e^4x + 3e^-4x=6 Q2: log(4^x -1) log(2^x +1)+1 Q3: (ln X)^2 = 3 ln x?
回答 (1)
2015-10-04 9:41 pm
✔ 最佳答案
1. y = e^(4x)0 = e^(4x) + 3e^(-4x) - 6
= e^(8x) + 3 - 6e^(4x)
= y^2 - 6y + 3
y = 3 +- √(9 - 3) = 3 +- √6
4x = ln(3 +- √6)
x = [ln(3 +- √6)]/4
2. log(4^x -1) log(2^x +1)+1
沒有等號無法演算
3. y = ln(x)
0 = (ln X)^2 - 3 ln x
= y^2 - 3y
= y(y - 3)
y =\= 0
y = 3
x = e^3
收錄日期: 2021-04-18 00:22:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151004050230AAXoCyy