let k be a constant. If the quadratic function y=3x^2+2kx-k>0 for all real values of x, then the ranges of values of k=?
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2015-10-02 5:00 pm
✔ 最佳答案
y = 3x² + 2kx - k > 0 是指 No Solutions when 3x² + 2kx - k = 0http://s18.postimg.org/latleq5t3/image.png
收錄日期: 2021-04-23 23:45:15
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