國二 因式分解 如圖片?
回答 (3)
2015-10-02 1:59 am
✔ 最佳答案
Sol(x－2)(x－1)(x+2)(x+4)+2x^2
=(x－2)(x+2)(x－1)(x+4)+2x^2
=(x^2－4)(x^2－4+3x)+2x^2
=(x^2－4)^2+3x(x^2－4)+2x^2
=(x^2－4+x)(x^2－4+2x)
=(x^2+x－4)(x^2+2x－4)
2015-10-02 11:33 am
(x-2)(x-1)(x+2)(x+4)+2x^2
=(x-2)(x+2)(x-1)(x+4)+2x^2
=(x^2-4)(x^2 +4x-x-4)+2x^2
=(x^2-4)(x^2+3x-4)+2x^2
=(x^2-4)^2+3x(x^2-4)+2x^2
=(x^2-4+x)(x^2-4+2x)
=(x^2+x-4)(x^2+2x-4)
=(x-2)(x+2)(x-1)(x+4)+2x^2
=(x^2-4)(x^2 +4x-x-4)+2x^2
=(x^2-4)(x^2+3x-4)+2x^2
=(x^2-4)^2+3x(x^2-4)+2x^2
=(x^2-4+x)(x^2-4+2x)
=(x^2+x-4)(x^2+2x-4)
收錄日期: 2021-04-18 13:56:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20151001175236AAhiC6Z