A 1300-kg car moving on a horizontal surface has speed v = 50 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.7 m .
What is the spring stiffness constant of the spring?
A 1300-kg car moving on a horizontal surface has speed v = 50 km/h?
2015-10-01 4:24 am
回答 (1)
2015-10-01 4:41 am
kinetic energy of car = (1/2)mv²
Gets converted into spring's potential energy = (1/2)kx²
so we get (1/2)mv² = (1/2)kx²
k = mv²/x²
k = 1300 kg * (50 km/hr *1000 m/1km * 1hr/3600 sec)² / (2.7 m)²
k = 34399 N/m
Gets converted into spring's potential energy = (1/2)kx²
so we get (1/2)mv² = (1/2)kx²
k = mv²/x²
k = 1300 kg * (50 km/hr *1000 m/1km * 1hr/3600 sec)² / (2.7 m)²
k = 34399 N/m
收錄日期: 2021-04-21 14:28:04
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https://hk.answers.yahoo.com/question/index?qid=20150930202443AA838s1