For the following precipitation reaction:
2Na3PO4(aq)+3CuCl2(aq) -->Cu3(PO4)2(s) + 6NaCl(aq)
Assume that the Na3PO4 and CuCl2 react according to their coefficients ratio.
What volume of the 0.175 M Na3PO4 solution is required to completely react with 95.4 mL of 0.102 M CuCl2?
Much help would be appreciated. Thanks!
Need help for Stoichiometry question.?
2015-09-30 2:11 am
回答 (1)
2015-09-30 5:28 am
2 Na3PO4 + 3 CuCl2 → Cu3(PO4)2 + 6 NaCl
(95.4 mL) x (0.102 M CuCl2) x (2 mol Na3PO4 / 3 mol CuCl2) / (0.175 M Na3PO4) = 37.1 mL Na3PO4
(95.4 mL) x (0.102 M CuCl2) x (2 mol Na3PO4 / 3 mol CuCl2) / (0.175 M Na3PO4) = 37.1 mL Na3PO4
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