微積分，請問圈起來的題目怎麼解?
回答 (2)
2015-09-29 3:18 pm
✔ 最佳答案
先求斜率dy/dx=2x對於斜率是2x的切線通過y=x^2 於 (m, m^2)這點
則可推出切線公式是y=2mx-m^2
(0, a)代入切線公式, 得m^2=-a
m要有解的話, a<0
將(a, 0)代入切線公式, 0=(2a-m)m
要有解的話m=0, 或a=m/2
2015-09-29 3:06 pm
y'=2x
(a) (0,a) => (0,0)
Tangent line: y-0=2(0)(x-0)
y=0
(b) (a,0) =>(0,0)
Tangent line: y=0
Are there any restrictions on the constant a?
ANS: a must be 0
(a) (0,a) => (0,0)
Tangent line: y-0=2(0)(x-0)
y=0
(b) (a,0) =>(0,0)
Tangent line: y=0
Are there any restrictions on the constant a?
ANS: a must be 0
收錄日期: 2021-05-03 13:37:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20150929061825AAhjEmo