find the tangent line to the graph of the given equation (x^2+y^2)^2 = 4x^2y (1,1) so far I have 2(x^2+y^2)(2x+2y dy/dx)= 8x dy/dx?
回答 (2)
2015-09-29 12:08 am
you are almost there.
now plug 1 for x and 1 for y and solve for dy/dx
now plug 1 for x and 1 for y and solve for dy/dx
2015-09-28 11:58 pm
sorry , right side is also a product....8 x y + 4 x² [ dy/dx ]....then put x = 1 = y to find the slope of the desired line
收錄日期: 2021-04-21 14:24:27
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