已知多項式6x次方+mx平方+8x+n可被3x平方-2x+1整除,則m=-13 n=-3 求算式??????????????ˊˇˋ?

2015-09-27 2:19 am

回答 (2)

2015-09-27 4:39 am
✔ 最佳答案
用分離係數長除法得:
6x^3+mx^2+8x+n=(3x^2-2x+1)(2x+((m+4)/3)+[((6+2(m+4)/3)x+((n-(m+4)/3)]

餘式=[((6+2(m+4)/3)x+((n-(m+4)/3)]=0
(6+2(m+4)/3)=0 , (n-(m+4)/3
==>18+2m+8=0 ,3n-m-4=0
==>m= -13,n=-3
2015-09-27 11:14 am
Sol
          2x-3
        ─────────────
3x2-2x+1)6x3+mx2+8x+n
        )6x3-4x2+2x
        )────────────
        )(m+4)x2+6x+n
        )   -9x2+6x-3
        )────────────
        )           0
So
m+4=-9,n=-3
m=-13


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